Hina Maeda and Yuda Yun, who competed in the finals of last year's 'Henryk Wieniawski International Violin Competition,' will take the stage for a duo recital.

Hina Maeda - Yuda Yoon Violin Duo Recital Poster. <br>[Photo by The Bridge Company]

Hina Maeda - Yuda Yoon Violin Duo Recital Poster.
[Photo by The Bridge Company]

View original image

On the 11th, The Bridge Company announced that Hina Maeda, the winner of the Wieniawski Competition, and Yuda Yun, a finalist, will perform at the IBK Chamber Hall in Seoul Arts Center on September 3rd.


The Wieniawski Competition was established to commemorate the 100th anniversary of the birth of Henryk Wieniawski (1835?1880), a representative Polish violinist and composer. It began in 1935 and is held every five years in Pozna?, Poland, as a prestigious international violin competition. The first winner in 1935 was the legendary violinist Ginette Neveu, with David Oistrakh placing second in 1935, and Igor Oistrakh winning first place in 1952.


Korean violinists who have participated in this competition include Kim Bom-sori (2nd place in 2016), Han Su-jin (2nd place in 2001), and Yoon So-young (1st place in 2011).



At the performance, Maeda and Yun will each play unaccompanied violin pieces that they performed during the first round of the competition. In the second half, they will showcase their best synergy with works for two violins.


This content was produced with the assistance of AI translation services.

© The Asia Business Daily(www.asiae.co.kr). All rights reserved.

Today’s Briefing